(2x^2-17x)/2=42

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Solution for (2x^2-17x)/2=42 equation:


x in (-oo:+oo)

(2*x^2-(17*x))/2 = 42 // - 42

(2*x^2-(17*x))/2-42 = 0

(2*x^2-17*x)/2-42 = 0

(2*x^2-17*x)/2+(-42*2)/2 = 0

2*x^2-17*x-42*2 = 0

2*x^2-17*x-84 = 0

2*x^2-17*x-84 = 0

2*x^2-17*x-84 = 0

DELTA = (-17)^2-(-84*2*4)

DELTA = 961

DELTA > 0

x = (961^(1/2)+17)/(2*2) or x = (17-961^(1/2))/(2*2)

x = 12 or x = -7/2

(x+7/2)*(x-12) = 0

((x+7/2)*(x-12))/2 = 0

((x+7/2)*(x-12))/2 = 0 // * 2

(x+7/2)*(x-12) = 0

( x+7/2 )

x+7/2 = 0 // - 7/2

x = -7/2

( x-12 )

x-12 = 0 // + 12

x = 12

x in { -7/2, 12 }

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